We prefer $\displaystyle\frac{\sqrt{2}}{2}$ to $\displaystyle\frac{1}{\sqrt{2}}$ and $\displaystyle\frac{\sqrt{6}}{3}$ to $\displaystyle\frac{\sqrt{2}}{\sqrt{3}}$.
• When the denominator is a simple surd, we multiply both the denominator and the numerator by the surd $$\frac{2}{\Tblue{\sqrt{10}}} = \frac{2\Tgreen{\sqrt{10}}}{\Tblue{\sqrt{10}}\times \Tgreen{\sqrt{10}}} = \frac{2\sqrt{10}}{10} = \frac{\sqrt{10}}{5}.$$
The conjugate of $\Tblue{\sqrt{3} + \sqrt{2}}$ is $\Tgreen{\sqrt{3}-\sqrt{2}}$. This helps us to simplify the following fraction. $$\frac{1}{\Tblue{\sqrt{3} + \sqrt{2}}} = \frac{1}{\Tblue{\sqrt{3} + \sqrt{2}}} \times \frac{\Tgreen{\sqrt{3} - \sqrt{2}}}{\Tgreen{\sqrt{3} - \sqrt{2}}} = \sqrt{3} - \sqrt{2}$$